\( \{ {z = 0} \} \)-contour.
Now let's set our output variable, \( z \), equal to zero.
\[
\begin{align}
&\bigl\{ {x^2 + y^2 = 0} \bigr\}
\end{align}
\]
To satisfy this equation both \( x \) and \( y \) must be zero. The only point \( (x, y) \) that satisfies this equation is \( (0, 0) \). In other words, the horizontal slice at height zero only intersects the bowl at one point, the origin.