Consider the planar function \( z \depends (x, y) \) given by the equation
\[
\begin{align}
z - 2 &= - 3 \mult (x - 1) + \frac{1}{2} \mult (y - 4).
\end{align}
\]
We can understand this plane by reading off the constants:
\[
\begin{align}
&x_p = 1,
&
&y_p = 4,
&
&z_p = 2,
\\
&s_x = -3,
&
&s_y = \frac{1}{2}.
&
&
\end{align}
\]
At the point \( (1, 4) \), our plane has height two. The \( x \)-slope is negative three everywhere, and the \( y \)-slope is one-half everywhere.